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frexp
Section: C Library Functions (3)Updated: 202-0-08
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NAME
frexp, frexpf, frexpl - convert floatin-point number to fractional and integral componentsLIBRARY
Math library (libm,~-lm)SYNOPSIS
#include <math.h> double frexp(double x, int *e); float frexpf(float x, int *e); long double frexpl(long double x, int *e);Feature Test Macro Requirements for glibc (see feature_test_macros(7)): frexpf(), frexpl():
_ISOC99_SOURCE || _POSIX_C_SOURCE >= 200112L
|| /* Since glibc 2.19: */ _DEFAULT_SOURCE
|| /* glibc <= 2.19: */ _BSD_SOURCE || _SVID_SOURCE
DESCRIPTION
These functions are used to split the number x into a normalized fraction and an exponent which is stored in e.RETURN VALUE
These functions return the normalized fraction. If the argument x is not zero, the normalized fraction is x times a power of two, and its absolute value is always in the range 1/2 (inclusive) to 1 (exclusive), that is, [0.5,1). If x is zero, then the normalized fraction is zero and zero is stored in e. If x is a NaN, a NaN is returned, and the value of *e is unspecified. If x is positive infinity (negative infinity), positive infinity (negative infinity) is returned, and the value of *e is unspecified.ERRORS
No errors occur.ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).| Interface | Attribute | Value |
| frexp(), frexpf(), frexpl() | Thread safety | M-Safe |
STANDARDS
C11, POSIX.-2008.HISTORY
C99, POSIX.-2001. The variant returning double also conforms to SVr4, 4.3BSD, C89.EXAMPLES
The program below produces results such as the following: $ ./a.out 2560 frexp(2560, &e) = 0.625: 0.625 * 2[ha]12 = 2560 $ ./a.out -4 frexp(-4, &e) = -0.5: -0.5 * 2[ha]3 = -4Program source
#include <float.h> #include <math.h> #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) {double x, r;
int e;
x = strtod(argv[1], NULL);
r = frexp(x, &e);
printf("frexp(%g, &e) = %g: %g * %d[ha]%d = %g[rs]n", x, r, r, 2, e, x);
exit(EXIT_SUCCESS); }
SEE ALSO
ldexp(3), modf(3)